(27/125)^(x+2)=25/9

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Solution for (27/125)^(x+2)=25/9 equation: 



(27/125)^(x+2)=25/9

We move all terms to the left:

(27/125)^(x+2)-(25/9)=0



Domain of the equation: 125)^(x+2)!=0

x∈R



We add all the numbers together, and all the variables

(+27/125)^(x+2)-(+25/9)=0

We get rid of parentheses

(+27/125)^(x+2)-25/9=0

We calculate fractions


()/125^x+(-3125x)/125^x=0

We multiply all the terms by the denominator


(-3125x)+()=0

We add all the numbers together, and all the variables

(-3125x)=0

We get rid of parentheses

-3125x=0

x=0/-3125

x=0

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